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WAEC Mathematics 2015 Paper
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© africaexams.com
Question : 40
Total: 45
Calculate the mean deviation of 5, 3, 0, 7, 2, 1
0.0
2.0
2.5
3.0
Validate
Solution:
mean =
x
=
∑
x
n
=
5
+
3
+
0
+
7
+
2
+
1
6
18
6
= 3
x
x
−
x
∣
x
−
x
∣
5
-2
2
3
0
0
0
-3
3
7
4
4
2
-1
1
1
-2
2
∑
|
x
−
x
|
12
hence, MD =
∑
x
−
x
/
n
}
12
6
= 2
© africaexams.com
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