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WAEC Mathematics 2013 Paper

Question : 35

Total: 48

Solution:

Concept:

Use Pythagoras' theorem to find the side of the square, then add all outer sides of the polygon.

Explanation:

\triangle PQR

\angle PQR = 90^\circ

, so it is a right-angled triangle.

By Pythagoras' theorem,

PR^2 = PQ^2 + QR^2

PR^2 = 24^2 + 10^2 = 576 + 100 = 676

Therefore,

PR = \sqrt{676} = 26\text{ cm}

Since

PRST

is a square, all its sides are equal:

PR = RS = ST = TP = 26\text{ cm}

The perimeter of polygon

PQRST

is the sum of its outer sides:

PQ + QR + RS + ST + TP

Perimeter

= 24 + 10 + 26 + 26 + 26 = 112\text{ cm}

Answer:

112\text{ cm}

(Option A).

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