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WAEC Mathematics 2013 Paper

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© africaexams.com

Question : 29

Total: 48

Given that P = x² + 4x - 2, Q = 2x - 1 and Q - p = 2, find x

-2
-1
1
2

Solution:

P = x² + 4x - 2, Q = 2x - 1

Q - p = 2, (2x - 1) - (x² + 4x - 2) = 2

2x - 1 - x² - 4x + 2 = 2

-2x - x² + 1

-x² - 2x - 1 = 0

x² + 2x + 1 = 0

x² + x + x + 1 = 0

x(x + 1) + 1(x + 1) = 0

(x + 1)(x + 1) = 0

x + 1 = 0 or x + 1 = 0

x = -1 or x = -1

x = -1

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