WAEC Mathematics 2011 Paper

Concept:To solve a linear equation with fractions, remove the denominators by simplifying both sides and collecting like terms.Explanation:Given: $\frac{3}{5}(2x - 1) = \frac{1}{4}(5x - 3)$Expanding both sides gives:$\frac{6x}{5} - \frac{3}{5} = \frac{5x}{4} - \frac{3}{4}$Bring the $x$-terms to one side and constants to the other:$\frac{6x}{5} - \frac{5x}{4} = \frac{3}{5} - \frac{3}{4}$Write each side over a common denominator of $20$:$\frac{24x - 25x}{20} = \frac{12 - 15}{20}$Simplify both numerators:$\frac{-x}{20} = \frac{-3}{20}$Multiply both sides by $20$ to eliminate the denominators:$-x = -3$Therefore:$x = 3$Answer:$x = 3$, which is option D.