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WAEC Mathematics 2011 Paper
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© africaexams.com
Question : 10
Total: 47
The cross section section of a uniform prism is a right-angled triangle with sides 3cm. 4cm and 5cm. If its length is 10cm. Calculate the total surface area
142cm
2
132cm
2
122cm
2
112cm
2
Validate
Solution:
A prism has 3 rectangular faces and 2 triangular faces and 2 rectangular faces = 10(3 + 4 + 5) = 120
Area of triangular faces =
√
s
(
s
−
a
)
(
s
−
b
)
(
s
−
c
)
where s =
a
+
b
+
c
2
=
3
+
4
+
5
2
=
12
2
= 6
Area of
△
=
√
6
(
6
−
30
(
6
−
4
)
(
6
−
5
)
=
√
6
×
3
×
2
×
1
= 6
Area of triangle faces = 2 x 6 = 12cm
2
Total surface area = Area of rectangular face + Area of
△
= 120 + 12
= 132cm
2
© africaexams.com
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