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WAEC Mathematics 2010 Paper
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© africaexams.com
Question : 26
Total: 49
The mean age of R men in a club is 50 years, Two men aged 55 and 63, left the club and the mean age reduced by 1 year. Find the value of R
18
20
22
28
Validate
Solution:
mean age =
sum of ages
no. of men
50
=
sum
R
sum = 50R.....(1)
Sum of ages of the men that left = 55 + 63 = 188
remaining sum = 50R - 118
remaining no. of men = R - 2
now mean age = 50 - 1 = 49 years
49 =
50
R
−
118
R
−
2
49(R - 2) = 50R - 118
49R - 50R = -188 - 98
-R = -20
R = 20
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