Concept:Use substitution to make the term containing Q vanish, then solve for P.Explanation:Given: 5x+7≡P(x+3)+Q(x−1)Put x=1 so that the factor (x−1) becomes zero.Then, LHS: 5(1)+7=5+7=12RHS: P(1+3)+Q(1−1)=4P+Q(0)=4PSo, 12=4PDivide both sides by 4: P=412=3Answer:P=3Correct option: A. 3