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WAEC Further Mathematics 2021 Paper
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© africaexams.com
Question : 3
Total: 38
Given that
M
=
(
3
2
−
1
4
)
and
N
=
(
5
6
−
2
−
3
)
, calculate
(
3
M
−
2
N
)
(
1
6
1
18
)
(
−
1
−
6
1
18
)
(
1
6
−
1
−
18
)
(
−
1
−
6
−
1
−
18
)
Validate
Solution:
3
M
=
3
(
3
2
−
1
4
)
=
(
9
6
−
3
12
)
2
N
=
2
(
5
6
−
2
−
3
)
=
(
10
12
−
4
−
6
)
(
3
M
−
2
N
)
=
(
9
6
−
3
12
)
−
(
10
12
−
4
−
6
)
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