Concept:For an equation to represent a circle, the coefficients of x2 and y2 must be equal, and there must be no xy term.Explanation:Check each equation for these conditions.Option A: 3x2+3y2+5x+7y=5. Divide by 3; coefficients of x2 and y2 are equal, so it is a circle.Option B: x2+y2+5x+4y=0. Coefficients are both 1, so it is a circle.Option C: 5x2+5y2−16=0. Divide by 5; coefficients are equal, so it is a circle.Option D: x2−y2+3x−5y=2. The coefficients are +1 and −1. Since they are not equal, it cannot be a circle; it represents a hyperbola.Answer:D. x2−y2+3x−5y=2