Solve; P/2 + k/3 = 5 and 2p = k = 6 simultaneously

Correct Answer is : p = 6, k = 6

Correct Answer is : p = 6, k = 6

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WAEC Further Mathematics 2019 Paper

Question : 2

Total: 39

Solve;

\frac{P}{2} + \frac{k}{3}

= 5 and 2p = k = 6 simultaneously

Solution:

Concept:

If two linear equations are given, solve them simultaneously to find the values of the variables that satisfy both equations.

Explanation:

Given the pair of equations:

\frac{p}{2}+\frac{k}{3}=5 \quad \text{and} \quad 2p-k=6.

Multiply the first equation by

6

to remove denominators:

3p+2k=30.

Express

k

from the second equation:

k=2p-6.

Substitute

k=2p-6

into

3p+2k=30

3p+2(2p-6)=30.

Simplify:

3p+4p-12=30 \Rightarrow 7p=42 \Rightarrow p=6.

Put

p=6

into

2p-k=6

12-k=6 \Rightarrow k=6.

Thus the values are

p=6

and

k=6

Answer:

p = 6

k = 6

Option C.

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