log2(12x−10)=1+log2(4x+3)
Recall, 1=log22, so
log2(12x−10)=log22+log2(4x+3)
= log2(12x−10)=log2(2(4x+3))
implies(12x−10)=2(4x+3)∴12x−10=8x+6
12x−8x=4x=6+10=16impliesx=4