3x−1(x−2)2=A(x−2)+Bx(x−2)2
3x−1(x−2)2=A(x−2)+Bx(x−2)2
Comparing, we have
3x−1=Ax−2A+Bximplies−2A=−1;A+B=3
∴A=12;B=52
= 12(x−2)+5x2(x−2)2