Concept:Scalar multiplication and subtraction of column vectors.Explanation:First, compute 2a.2a=2(32)=(64).Next, compute 41b.41b=41(4−1)=(1−41).Now subtract component-wise.First component: 4−(−41)=417.Second component: 6−1=5.Hence, 2a−41b=(5417).Answer:(5417), which is Option B.