Concept:Use partial fractions by combining the right-hand side and then equating coefficients of like powers of x.Explanation:Multiply both sides by (x+6)(x+3):2x=P(x+3)+Q(x+6)Expand the right-hand side:2x=Px+3P+Qx+6QGroup the x terms and constant terms:2x=(P+Q)x+(3P+6Q)Equate coefficients of x: P+Q=2 ...(i)Equate constant terms: 3P+6Q=0 ...(ii)From (ii): 3P=−6Q, so P=−2QSubstitute P=−2Q into (i):−2Q+Q=2⇒−Q=2⇒Q=−2Then P=−2(−2)=4Hence P=4 and Q=−2Answer:Option C: P=4 and Q=−2