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WAEC Chemistry 2025 Paper

Question : 27

Total: 50

If 25cm

^3

Solution:

Concept:

Solubility is the amount of solute in moles dissolved in

1 \, \text{dm}^3

of solution.

Explanation:

Given volume is

25 \, \text{cm}^3

Convert this volume to

\text{dm}^3

25 \, \text{cm}^3 = \frac{25}{1000} \, \text{dm}^3 = 0.025 \, \text{dm}^3

Amount of solute present is

0.02 \, \text{mol}

Solubility is calculated as:

\text{Solubility} = \frac{\text{moles of solute}}{\text{volume in } \text{dm}^3}

Substitute the values:

\text{Solubility} = \frac{0.02}{0.025} = 0.8 \, \text{mol dm}^{-3}

Answer:

0.8 \, \text{mol dm}^{-3}

(Option B).

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