Concept:Ethanol is a primary alcohol that can be oxidized by acidified potassium dichromate.The final product depends on the amount of oxidizing agent used.Explanation:Here, excess acidified K2Cr2O7 is used.Excess oxidant completely oxidizes ethanol beyond the aldehyde stage.Ethanol first converts to ethanal, which is then oxidized further to ethanoic acid.The overall reaction is:CH3CH2OH+[O]excessK2Cr2O7/H+CH3COOHDuring the reaction, the orange dichromate is reduced to green Cr3+ ions.This oxidation does not produce ethene, ether, or ethane.Answer:The product is CH3COOH (ethanoic acid).Therefore, the correct option is C. CH3COOH.