The volume of 22g of CO₂ at stp is equivalent to [C =12, O =16, molar volume at stp = 22.4 dm³ ]

Correct Answer is : 11.2 dm3³3

Correct Answer is : 11.2 dm3³3

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WAEC Chemistry 2024 Paper

Question : 32

Total: 50

_2

^3

]

Solution:

Concept:

At standard temperature and pressure (STP),

1

mole of any gas occupies

22.4\ \mathrm{dm}^3

. The volume of a gas is found by multiplying the number of moles by the molar volume.

Explanation:

Find the molar mass of

\mathrm{CO}_2

Molar mass

= 12 + (2 \times 16) = 44\ \mathrm{g/mol}

Calculate the number of moles of

\mathrm{CO}_2

22\ \mathrm{g}

n = \frac{\text{mass}}{\text{molar mass}} = \frac{22}{44} = 0.5

mol.

Use the gas volume formula:

V = n \times \text{molar volume}

V = 0.5 \times 22.4 = 11.2\ \mathrm{dm}^3

Answer:

11.2\ \mathrm{dm}^3

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