Concept:In a cell notation, the anode (oxidation) half-cell is written on the left and the cathode (reduction) half-cell on the right, separated by the salt bridge //.Explanation:From the diagram, electrode A acts as the anode. Oxidation occurs at A: A→A3++3e−. Electrode B acts as the cathode. Reduction occurs at B: B2++2e−→B. So the anode half-cell is written as A/A3+, and the cathode half-cell is written as B2+/B. Joining them with the salt bridge gives: A/A3+//B2+/B.Answer:D. A/A3+//B2+/B