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WAEC Chemistry 2017 Paper

Question : 49

Total: 50

Solution:

Concept:

Primary alkanols are saturated alcohols with the general formula

\mathrm{C}_{n}\mathrm{H}_{2n+1}\mathrm{OH}

Explanation:

Given molar mass is

60

So,

12n + (2n + 2) + 16 = 60

Simplifying:

14n + 18 = 60

Thus,

14n = 42

, so

n = 3

Therefore, the molecular formula is

\mathrm{C}_{3}\mathrm{H}_{7}\mathrm{OH}

Since it is a primary alkanol, the

-\mathrm{OH}

group is attached to an end carbon atom.

Hence, the structural formula is

\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CH}_{2}\mathrm{OH}

Answer:

\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CH}_{2}\mathrm{OH}

(propan-1-ol).

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