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WAEC Chemistry 2011 Paper

Question : 25

Total: 46

Solution:

Concept:

At constant pressure, the volume of a gas is directly proportional to its absolute temperature. This is Charles's Law:

\frac{V_1}{T_1} = \frac{V_2}{T_2}

Explanation:

Given:

V_1 = 220\ \mathrm{cm}^3

T_1 = 300\ \mathrm{K}

, and

V_2 = 250\ \mathrm{cm}^3

Rearrange Charles's Law to find the new temperature:

T_2 = \frac{V_2 \times T_1}{V_1}

Substitute the values:

T_2 = \frac{250 \times 300}{220}

Calculate:

T_2 = \frac{75000}{220} = 340.9\ \mathrm{K} \approx 341\ \mathrm{K}

Thus, the temperature of the gas becomes approximately

341\ \mathrm{K}

Answer:

341\ \mathrm{K}

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