The equivalent capacitance of the capacitors in the circuit above
Capacitance in parallel = one at the top + one under = 2C
The two in the middle are in series = C2\frac{C}{2}2C
The equivalent capacitance of the capacitors in the circuit above = C2\frac{C}{2}2C + 2C = 52\frac{5}{2}25C
