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JAMB Physics 2024 Paper

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Question : 17

Total: 125

A wheelbarrow inclined at 60º to the horizontal is pushed with a force of 150N. What is the horizontal component of the applied force

130N
75N
60N
50N

Solution:

The horizontal component F $_{x}$ can be calculated using the formula: F $_{x}$ = F⋅ cos ( $\theta$ )

F = 150N and $\theta$ = 60º

F $_{x}$ = 150 x 0.5 = 75N (cos 60º = 0.5)

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