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JAMB Physics 2024 Paper

Question : 107

Total: 125

Solution:

Concept:

Electric field intensity is the force acting per unit positive charge.

Explanation:

Use the formula

E = \frac{F}{q}

Given:

F = 8 \, \mathrm{N}

and

q = 4 \, \mu\mathrm{C}

Convert the charge:

q = 4 \, \mu\mathrm{C} = 4.0 \times 10^{-6} \, \mathrm{C}

Substitute the values into the formula:

E = \frac{8}{4.0 \times 10^{-6}}

Simplify:

E = 2.0 \times 10^6 \, \mathrm{NC}^{-1}

Hence, the electric field intensity is

2.0 \times 10^6 \, \mathrm{NC}^{-1}

Answer:

E = 2.0 \times 10^6 \, \mathrm{NC}^{-1}

Correct option: A.

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