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JAMB Physics 2023 Paper
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© africaexams.com
Question : 38
Total: 65
A beam of light travelling in water is incident on a glass which is immersed in the water. The incident beam makes an angle of
4
0
∘
40^{\circ}
4
0
∘
with the normal. Calculate the angle of refraction in the glass.
[Refractive index of water = 1.33, Refractive index of glass = 1.5]
29.3
6
∘
29.36^{\circ}
29.3
6
∘
25.3
7
∘
25.37^{\circ}
25.3
7
∘
37.2
1
∘
37.21^{\circ}
37.2
1
∘
34.7
5
∘
34.75^{\circ}
34.7
5
∘
Validate
Solution:
n
1
n_1
n
1
=1.33;
n
2
n_2
n
2
=1.5; i=40°; r= ?
from snell's law:
n
1
n_1
n
1
x sin i=
n
2
n_2
n
2
x sin r
⇒1.33 x sin 40°=1.5 x sin r
⇒sin r = 0.5700
⇒r =
sin
−
1
\sin^{-1}
sin
−
1
(0.5700)
⇒ r = 34.75
© africaexams.com
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