f= 15cm (diverging mirror); u= -35cm(because object is in front of the mirror) v=? ⇒1f = 1v - 1u ⇒ 115 = 1v - 1−35 ⇒ 115 - 135 = 1v ⇒ 1054 = 1v v = 1054 = 26.25cm ∴The image is 26.25cm behind the mirror