JAMB Physics 2023 Paper

The patient cannot see clearly an object closer than 50 cm

Therefore, the patient needs a lens that would enable him see clearly, objects placed 25 cm from the lensSo, we take the object to a distance of 25 cm from the lens so that the image forms at 50 cm in front of the lensu=25cm ;v=-50cm (virtual image); p=$\frac{1}{f}$=$\frac{1}{u}$ + $\frac{1}{v}$⇒$\frac{1}{f}$ =$\frac{1}{50}$⇒$\frac{1}{f}$ = $\frac{1}{25}$-$\frac{1}{50}$⇒$\frac{1}{f}$ = f = 50cm =0.5m⇒$\frac{1}{f}$ = $\frac{2-1}{50}$ p = $\frac{1}{f}$ p = $\frac{1}{0.5}$ p = 2 diopters ; The patient needs a converging lens with a power of 2 diopters