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JAMB Physics 2023 Paper

Question : 13

Total: 65

m^2

[Thermal conductivity of water (k) = 0.6071 Wm-1K-1]

Solution:

Concept:

Heat conduction through a material depends on the thermal conductivity, area, temperature difference, and thickness.

Explanation:

Surface temperature is

25^\circ\mathrm{C}

and bottom temperature is

15^\circ\mathrm{C}

So the temperature difference is

\Delta T = 25 - 15 = 10\,\mathrm{K}.

The depth is

L = 1.5\,\mathrm{m}

and the surface area is

A = 620\,\mathrm{m}^2

The rate of heat transfer by conduction is

\frac{Q}{t} = \frac{kA\Delta T}{L}.

Substitute the given values:

\frac{Q}{t} = \frac{0.6071 \times 620 \times 10}{1.5}.

\frac{Q}{t} = 2509.35\,\mathrm{W} \approx 2.5\,\mathrm{kW}.

Answer:

2.5\,\mathrm{kW}

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