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JAMB Physics 2022 Paper

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Question : 22

Total: 40

The potential energy in an elastic string of force constant k, which has an extension X is?

kX
KX ${}^2$
½KX ${}^2$
½K

Solution:

Concept:

The energy stored in a stretched elastic material equals the work done in extending it.

Explanation:

The elastic potential energy is given by the formula

E = \frac{1}{2} k e^2

.

Here,

k

is the force constant and

e

is the extension.

The extension is

X

, so substituting

e = X

gives

E = \frac{1}{2} k X^2

.

Answer:

\frac{1}{2} k X^2

Correct option: C.

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