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JAMB Physics 2022 Paper

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Question : 15

Total: 40

A tuning fork having a frequency of 312 Hz emits a wave which has a wavelength of 1.10 m. Calculate the velocity of sound

312.0 ms $^{-1}$
110.0 ms $^{-1}$
343.2 ms $^{-1}$
686.4 ms $^{-1}$

Solution:

Concept:

The velocity of a wave is the product of its frequency and wavelength.

Explanation:

Given: frequency

f = 312 \, \mathrm{Hz}

and wavelength

\lambda = 1.10 \, \mathrm{m}

.

Use the wave equation:

v = f \lambda

.

Substitute the values:

v = 312 \times 1.10

v = 343.2 \, \mathrm{m \, s^{-1}}

Answer:

The velocity of sound is

343.2 \, \mathrm{m \, s^{-1}}

.

Correct option: C.

343.2 \, \mathrm{m \, s^{-1}}

.

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