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JAMB Physics 2021 Paper

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Question : 35

Total: 40

The lowest note emitted by a stretched string has a frequency of 40Hz. How many overtones are there between 40Hz and 180Hz?

4
3
2
1

Solution:

f $_{0}$ = 40H $_{3}$

1st overtone = 2f $_{0}$ = 80H $_{3}$

2nd overtone = 3f $_{0}$ = 120H $_{3}$

3rd overtone = 4f $_{0}$ = 160H $_{3}$

4th overtone = 5f $_{0}$ = 200H $_{3}$

$∴$ Number of overtones between 40H $_{3}$ and 180H $_{3}$ = 3

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