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JAMB Physics 2021 Paper

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Question : 32

Total: 40

Calculate the mass of ice that would melt when 2kg of copper is quickly transferred from boiling water to a block of ice without heat loss (specific heat capacity of copper = 400Jkg

^{1}

^{-1}

, latent heat of fusion of ice = 3.3 x 10

^{5}

^{-1}

)

$\frac{8}{33}$ kg
$\frac{3.3}{80}$ kg
$\frac{80}{33}$ kg
$\frac{3.3}{8}$ kg

Solution:

mc $\Delta\theta$ = m $\lambda$ f

2 x 400 (100 - 0) = m(3.3 x 10 $^{5}$ )

m = $\frac{2 \times 400 \times 100}{3.3 \times 10^{5}} = \frac{8}{33}$ kg

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