JAMB Physics 2021 Paper

Given $\frac{m_{1}}{m_{2}} = \frac{3}{1}$ $\Rightarrow$ m$_{1}$ = 3m$_{2}$

$\frac{a_{1}}{a_{2}} = \frac{2}{9}$ = a$_{1}$ = $\frac{2a_{2}}{9}$

$\frac{F_{1}}{F_{2}}$ = ?

Since F = ma

$\Rightarrow$ $\frac{F_{1}}{F_{2}} = \frac{m_{1}a_{1}}{m_{2}a_{2}}$ = $\frac{(3 \text{ not } m_{2})(2 \text{ not } a_{2})}{\text{not } m_{2} a_{2} \text{ not } a_{3}}$

$\frac{F_{1}}{F_{2}} = \frac{2}{3}$ $\Rightarrow$ 2:3