JAMB Physics 2020 Paper

When K is open. Total Resistance = 8 + 2 = 10$\Omega$

1 = $\frac{V}{\Omega}$ = $\frac{6v}{\Omega}$ = 0.6A

Where K is closed, $\frac{1}{8} + \frac{1}{8} = \frac{1}{\Omega}$

$\frac{2}{8} = \frac{1}{\Omega}$

$\Omega$ = $\frac{8}{2}$ = 4$\Omega$

$\Omega$ = $\frac{8}{2}$ = 4$\Omega$

4$\Omega$ in series with 2$\Omega$= 6$\Omega$

1 = $\frac{V}{\Omega}$ = $\frac{6}{6}$ = 1A

1 - 0.6A = 0.4A increase