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JAMB Physics 2020 Paper

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Question : 29

Total: 38

The lower and upper fixed points marked on a Mercury-in-glass thermometer are 210mm apart. The end of the mercury column in the tube is 49mm above the lower fixed point in a room. What is the temperature of the room in degrees Celsius?

55.3 $^{\circ}$ C
23.3 $^{\circ}$ C
49.0 $^{\circ}$ C
16.43 $^{\circ}$ C

Solution:

$\frac{49-0}{210-0}$ = $\frac{\theta-0}{100-\theta}$

$\frac{49}{210} = \frac{\theta}{100}$

49 x 100 = 210 x $\theta$

$\theta = \frac{4900}{210}$ = 23.3 $^{\circ}$

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