JAMB Physics 2020 Paper

Relative density of solid

$\frac{\text{weight of solid}}{\text{weight of an equal volume of water}}$

= $\frac{4.8}{4.8 - 2.8}$

= $\frac{4.8}{2}$ = 2.4

Relative density of liquid

= $\frac{\text{Weight of liquid kerosine}}{\text{Weight of an equal volume of water}}$

= $\frac{4.8 - 3.2}{4.8 - 2.8}$ = $\frac{1.6}{2}$ = 0.8

= $\frac{\text{Ratio of relative density of solid}}{\text{Relative density of Kerosine}}$

= $\frac{\text{density of solid}}{\text{density of Kerosine}}$

= $\frac{2.4}{0.8}$

= 3