Test Index

JAMB Physics 2018 Paper

Question : 58

Total: 87

\frac{1}{3}

Solution:

Concept:

A floating object displaces its own mass of liquid. Density and relative density are found from mass over displaced volume.

Explanation:

Since

\frac{1}{3}

of the cube is above the liquid, the submerged fraction is

\frac{2}{3}

Side length

= 50

= 0.5

Volume submerged

= \frac{2}{3}(0.5)^3 = 0.0833 \, \text{m}^3

Mass of liquid displaced equals mass of the cube:

75

kg.

Density of liquid

= \frac{75}{0.0833} = 900 \, \text{kg m}^{-3}

Relative density

= \frac{900}{1000} = 0.9

Answer:

0.90

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