Test Index

JAMB Physics 2018 Paper

Question : 43

Total: 87

Solution:

Concept:

Impulse is equal to the change in momentum of the ball.

Explanation:

Mass of ball,

m = 800\text{ g} = 0.8\text{ kg}

Initial velocity towards the wall,

u = +5\text{ m/s}

After rebounding with the same speed in the opposite direction, final velocity,

v = -5\text{ m/s}

Initial momentum:

p_i = mu = 0.8 \times 5 = 4.0\text{ kg m/s}

Final momentum:

p_f = mv = 0.8 \times (-5) = -4.0\text{ kg m/s}

Impulse experienced by the ball:

\text{Impulse} = \Delta p = p_f - p_i

\Delta p = -4.0 - 4.0 = -8.0\text{ kg m/s}

Magnitude of impulse

= 8.0\text{ kg m/s}

Answer:

8\text{ kg m/s}

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