Test Index

JAMB Physics 2018 Paper

Question : 39

Total: 87

Calculate the effective capacitance of the circuit in the diagram given

Solution:

Concept:

Capacitors in series and parallel are combined using the reciprocal rule and direct addition respectively.

Explanation:

The two

2\,\mu\mathrm{F}

capacitors in the series branch give:

\frac{1}{C_s} = \frac{1}{2} + \frac{1}{2} = 1

C_s = 1\,\mu\mathrm{F}

This

1\,\mu\mathrm{F}

is in parallel with the remaining

2\,\mu\mathrm{F}

capacitor, so:

C_{\text{eff}} = 1 + 2 = 3\,\mu\mathrm{F}

Answer:

3\,\mu\mathrm{F}

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