JAMB Physics 2018 Paper

From the law of conservation of linear momentum,

$m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2$

Since the collision is inelastic, we have

$(0.05 \times 200) - (0.95 \times 0) = (0.05 + 0.95)V$

$10 = V$

$V = 10\,\mathrm{m\,s}^{-1}$

Hence the Kinetic energy = $\frac{1}{2} (0.05 + 0.95) \times 10^2$

= $\frac{1}{2} \times 100$

= 50J