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JAMB Physics 2017 Paper

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Question : 5

Total: 49

Calculate the upthrust on an object of volume 50cm3 which is immersed in liquid of density

10^{3}

kgm-3 [g = 10ms-2]

0.8N
2.5N
0.5N
1.0N

Solution:

Concept:

Upthrust equals the weight of the liquid displaced by the object.

Explanation:

Convert volume to

\text{m}^3

:

50\,\text{cm}^3 = 50 \times 10^{-6}\,\text{m}^3

.

Mass of liquid displaced = density × volume.

So,

m = 10^3 \times 50 \times 10^{-6} = 0.05\,\text{kg}

.

Upthrust = weight of displaced liquid =

mg

.

Therefore, upthrust

= 0.05 \times 10 = 0.5\,\text{N}

.

Answer:

C.

0.5\,\text{N}

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