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JAMB Physics 2017 Paper

Question : 45

Total: 49

The velocity ratio of an inclined plane where angle of inclination in θ is

Solution:

Concept:

The velocity ratio of an inclined plane is the ratio of the distance moved by the effort to the distance moved by the load.

Explanation:

For an inclined plane, the effort moves along the length of the plane, while the load is lifted vertically through the height.

Thus,

V.R = \frac{\text{distance moved by effort}}{\text{distance moved by load}} = \frac{\text{length}}{\text{height}}

\theta

is the angle of inclination, then

\sin \theta = \frac{\text{height}}{\text{length}}

Therefore,

V.R = \frac{\text{length}}{\text{height}} = \frac{1}{\sin \theta}

Answer:

V.R = \frac{1}{\sin \theta}

, which is option D.

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