JAMB Physics 2017 Paper

Concept:Capacitors in parallel add directly, while capacitors in series combine by adding their reciprocals.Explanation:First, identify the two $2\mu F$ capacitors as being connected in parallel.For capacitors in parallel, the equivalent capacitance is the sum of the individual capacitances.So, $C_p = 2\mu F + 2\mu F = 4\mu F$This combined $4\mu F$ capacitor is then connected in series with the other $4\mu F$ capacitor in the circuit.For capacitors in series, use the reciprocal formula:$\frac{1}{C_{net}} = \frac{1}{4\mu F} + \frac{1}{4\mu F}$Add the fractions:$\frac{1}{C_{net}} = \frac{2}{4\mu F} = \frac{1}{2\mu F}$Taking the reciprocal gives:$C_{net} = 2\mu F$Answer:$2.0\mu F$ (Option D)