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JAMB Physics 2016 Paper

Question : 27

Total: 48

[R = 8.3jmol^-1K^-1]

Solution:

Concept:

Use the ideal gas equation to relate pressure, volume, number of moles, and temperature.

Explanation:

The ideal gas equation is

PV = nRT

Make temperature the subject:

T = \frac{PV}{nR}

Substitute the given values:

P = 7.6 \times 10^6 \, \text{Nm}^{-2}

V = 10^{-3} \, \text{m}^3

n = 6

moles, and

R = 8.3 \, \text{J mol}^{-1}\text{K}^{-1}

T = \frac{7.6 \times 10^6 \times 10^{-3}}{6 \times 8.3}

Simplify the numerator:

7.6 \times 10^6 \times 10^{-3} = 7.6 \times 10^3

Then

T = \frac{7.6 \times 10^3}{49.8} \approx 153

This corresponds to the option given as

153^\circ C

Answer:

153^\circ C

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