Test Index

JAMB Physics 2015 Paper

Question : 52

Total: 66

Solution:

Concept:

The peak value of an alternating voltage is related to its r.m.s value by the factor

\sqrt{2}

Explanation:

The r.m.s value is given as

V_{rms} = 200\ \text{V}

The relationship is

V_{rms} = \dfrac{V_{peak}}{\sqrt{2}}

Rearrange to find the peak value:

V_{peak} = V_{rms} \times \sqrt{2}

Substitute the given value:

V_{peak} = 200 \times 1.414

This gives

V_{peak} = 282.8\ \text{V} \approx 283\ \text{V}

Therefore, the approximate peak voltage is

283

volts.

Answer:

283

volts

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