Test Index

JAMB Physics 2015 Paper

Question : 33

Total: 66

Solution:

Concept:

Use the equation of motion for a body falling freely from rest,

s = ut + \frac{1}{2}gt^{2}

, where

u = 0

Explanation:

The ball is released from rest, so initial velocity

u = 0 \, \text{m/s}

Given:

s = 20 \, \text{m}

g = 10 \, \text{m/s}^{2}

Substitute into the equation:

20 = 0 \cdot t + \frac{1}{2} \times 10 \times t^{2}

This simplifies to:

20 = 5t^{2}

Divide both sides by 5:

t^{2} = 4

Take the positive square root:

t = \sqrt{4} = 2 \, \text{s}

Therefore, the ball takes 2 seconds to reach the ground.

Answer:

A. 2 sec

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