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JAMB Physics 2015 Paper

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Question : 31

Total: 66

If a mango fruit dropped at a height of 50 meters. How long does it reach the ground? (take g = 10m/s²)

2 sec
3 sec
4sec
3.2sec

Solution:

Concept:

A freely falling object starts from rest, so its initial velocity is zero.

Explanation:

Use the equation

s = ut + \frac{1}{2}gt^2

.

Given:

s = 50\,m

,

u = 0\,m/s

,

g = 10\,m/s^2

.

Substitute the values:

50 = 0 \times t + \frac{1}{2}(10)(t^2)

.

This simplifies to

50 = 5t^2

.

Divide both sides by 5:

t^2 = \frac{50}{5} = 10

.

Taking the square root:

t = \sqrt{10} \approx 3.16\,s

.

The closest answer is

3.2\,s

.

Answer:

t = 3.2

seconds.

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