Test Index

JAMB Physics 2014 Paper

Question : 22

Total: 41

Solution:

Concept:

The distance between successive crests is the wavelength

\lambda

, and the wave speed

v

is related to frequency

f

v = f\lambda

Explanation:

Convert the wavelength to metres:

\lambda = 15\,\text{cm} = 0.15\,\text{m}

The wave velocity is

v = 300\,\text{m/s}

Using the wave equation

v = f\lambda

, make frequency the subject:

f = \frac{v}{\lambda}

Substitute the values:

f = \frac{300}{0.15}\,\text{Hz}

Calculate the result:

f = 2000\,\text{Hz} = 2.0 \times 10^3\,\text{Hz}

Answer:

2.0 \times 10^3\,\text{Hz}

, which is option C.

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