A force of 500N 1 is applied to a steel wire of cross-sectional area 0.2m 2 , The tensile stress is

Correct Answer is : 2.5x103Nm-2

Correct Answer is : 2.5x103Nm-2

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JAMB Physics 2014 Paper

Question : 14

Total: 41

Solution:

Concept:

Tensile stress is the force applied per unit cross-sectional area of a material.

Explanation:

Stress is calculated using the formula:

\text{Stress} = \frac{\text{Force}}{\text{Area}}

Substitute the given values:

\text{Stress} = \frac{500\ \mathrm{N}}{0.2\ \mathrm{m}^2}

Perform the division:

\text{Stress} = 2500\ \mathrm{N\,m}^{-2}

Express in standard form:

2500 = 2.5 \times 10^3\ \mathrm{N\,m}^{-2}

This matches option D.

Answer:

2.5 \times 10^3\ \mathrm{N\,m}^{-2}

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