Test Index

JAMB Physics 2014 Paper

Question : 10

Total: 41

Solution:

Concept:

The kinetic energy just before impact equals the gravitational potential energy at the release height.

Explanation:

The object starts from rest at a height of

10 \, \text{m}

Its potential energy is

PE = mgh

Here,

m = 20 \, \text{kg}

g = 10 \, \text{m/s}^2

, and

h = 10 \, \text{m}

So,

PE = 20 \times 10 \times 10 = 2000 \, \text{J}

By energy conservation,

KE = PE

at the ground.

Therefore, the kinetic energy just before hitting the ground is

2000 \, \text{J}

Answer:

2000 \, \text{J}

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