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JAMB Physics 2013 Paper

Question : 8

Total: 43

Solution:

Concept:

Equate potential energy to kinetic energy and solve for the height.

Explanation:

For the moving body, kinetic energy is

K.E = \frac{1}{2}mv^2

For the similar body at height

h

, potential energy is

P.E = mgh

Given

P.E = K.E

, so

mgh = \frac{1}{2}mv^2

Mass cancels out:

gh = \frac{v^2}{2}

Therefore,

h = \frac{v^2}{2g}

Substitute

v = 5 \, \text{m/s}

and

g = 10 \, \text{m/s}^2

h = \frac{5^2}{2 \times 10} = \frac{25}{20} = 1.25 \, \text{m}

This is approximately

1.3 \, \text{m}

Answer:

1.3 \, \text{m}

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